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Re: [Omaha.pm] am I drunk.... code reduction? #2
> ?? I must be drunk? Doesn't
>
> if ($r[0] =~ /^COMP/) {
> $r[0] = $r[1];
> if ((not $r[0] =~ /HCOMP/) and (not $r[0] =~ /GCOMP/) and (not
$r[0] =~ /CCOMP/)) {
> $r[0] = "COMP";
> }
> }
>
> reduce to
>
> if ($r[0] =~ /^COMP/) {
> $r[0] = "COMP";
> }
>
> ??
[Answering my own question...]
No. If
@r = ("COMPX", "HCOMP");
then the original code would leave $r[0] as "COMPX" but my reduction
would change it to "COMP".
Ok, I'm only half drunk... (the other example still stands AFAICT)
(That is *not* the way I would have written this original, but my
reduction was wrong.)
Reduction stab 2:
if ($r[0] =~ /^COMP/) {
if ($r[1] =~ /[HGC]COMP/) {
$r[0] = $r[1];
} else {
$r[0] = "COMP";
}
}
Better, yes? No?
j